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  • Kimmo Alm aka "Sysop" from AnT has been spamming us for YEARS now, and has recently stepped it up. This shit has got to fucking stop. As promised, here are all of the e-mails he has sent me over the years (and my responses).

    We've done all we can do about him. We've banned THOUSANDS of proxies, and deleted OVER A HUNDRED THOUSAND spam posts. His attacks continue though, and we've reached the limit of what we can do.
    edit: we aren't going to add captcha.

    File : 1268284375.jpg-(127 KB, 300x427, Illlearnye.jpg)
    127 KB Anonymous 03/11/10(Thu)00:12 No.490035  
    Hey /sci/,
    are you manly enough to simplify
    1b2010b18+36b1656b14+35b126b10b21b188b16+21b1420b12+5b10b21b146b12+10b104b8+b22(1b167b14+15b1210b10+1b8)


    this isn't homework, I'm just a mathfag.
    >> Anonymous 03/11/10(Thu)00:14 No.490045
         File1268284446.jpg-(76 KB, 704x527, MotherOfGod2.jpg)
    76 KB
    Man, i don't even know where to begin.
    >> Anonymous 03/11/10(Thu)00:14 No.490046
    set b = 1, problem solved
    >> Anonymous 03/11/10(Thu)00:14 No.490056
    >>490035
    my fellow anon, this is one of those situations where you bite the bullet and load up maple
    >> Anonymous 03/11/10(Thu)00:16 No.490069
    >>490056
    I already know the answer, I was just seeing if anyone on /sci/ had the gusto to find the answer.
    >> Anonymous 03/11/10(Thu)00:16 No.490073
    I wouldn't have thought it was anyway. This goes beyond any reasonable homework (in that it is way too much repetition). I would do it if I gave a fuck, but it's just a stupid endeavor. Really, it's no different than when a 5th grader goes "What's 4*5*17*245*374*43?" Sure, it take a little while to do it, but it's easy.
    >> Anonymous 03/11/10(Thu)00:16 No.490076
         File1268284604.png-(218 KB, 426x349, 1268273883557.png)
    218 KB
    >>490045
    If I may, just plug this bitch into mathematica, and it is done.
    >> Anonymous 03/11/10(Thu)00:17 No.490087
    wow that seems like a boring, mindless problem, op
    >> Anonymous 03/11/10(Thu)00:17 No.490091
    >>490073
    Same here.
    >> Anonymous 03/11/10(Thu)00:18 No.490092
    >>490073
    Nah, this is funnier, because the answer is actually zero.
    >> Anonymous 03/11/10(Thu)00:18 No.490097
    multiply everything by b^36 to get rid of those pesky denominators
    >> OP 03/11/10(Thu)00:20 No.490112
    Okay guys, the answer is zero:
    1b2010b18+36b1656b14+35b126b10b21b188b16+21b1420b12+5b10b21b146b12+10b104b8+b22(1b167b14+15b1210b10+1b8)=0
    >> Anonymous 03/11/10(Thu)00:20 No.490118
    The fractions with the b^2 denominator can be separated, i.e. 1/(b^18 * b^2) - 8/(b^16 * b^2) + ...
    Not hard at all.
    >> Anonymous 03/11/10(Thu)00:21 No.490127
    >>490112
    multiply both sides by zero

    bam, simplified
    >> OP 03/11/10(Thu)00:22 No.490133
    >>490127
    No, but seriously, 1b2010b18+36b1656b14+35b126b10b21b188b16+21b1420b12+5b10b21b146b12+10b104b8+b22(1b167b14+15b1210b10+1b8)==0 is true for any b
    >> Anonymous 03/11/10(Thu)00:23 No.490138
    >>490133
    what about b=0
    >> OP 03/11/10(Thu)00:23 No.490142
    >>490138
    especially b=0
    >> Anonymous 03/11/10(Thu)00:24 No.490153
    >>490133
    not for b = 0
    >> Anonymous 03/11/10(Thu)00:24 No.490155
    >>490142
    It is pathetic that you called yourself a mathfag
    >> Anonymous 03/11/10(Thu)00:26 No.490171
    >>490092
    Oh, so it is. So it's like a fifth grader going "I bet you don't know what 37*3574*4357*354365*345745*100586*5270*0*35832*3567*574357*2*34576*45768927 is." Then laughing and going "It's zero!"
    >> OP 03/11/10(Thu)00:26 No.490172
    >>490155
    lol, I'm well aware it's undefined, but the limit is well defined, and if you fully simplify the expression you get one which is well defined for all b, I just don't feel like nit-picking on 4chan.
    >> Anonymous 03/11/10(Thu)00:39 No.490251
    >>490172
    Technically just because you simplified the division by zero away, you can't just pretend it doesn't exist.

    You're still supposed to say it's undefined for b = 0 even though it's not in the simplified form.

    I never liked it either, but the purpose is to preserve any conditions that may have been around in the original situation.
    >> Anonymous 03/11/10(Thu)00:41 No.490262
    b = 1 lol
    >> Anonymous 03/11/10(Thu)00:44 No.490279
    >>490262
    b = anything but zero lol
    >> Anonymous 03/11/10(Thu)09:28 No.492034
         File1268317700.png-(29 KB, 723x635, latex1.png)
    29 KB
    Hey /sci/,
    are you manly enough to figure out the formula for f1(X)?
    >> Anonymous 03/11/10(Thu)09:31 No.492041
         File1268317909.png-(48 KB, 730x920, latex2.png)
    48 KB
    Furthermore,
    are you manly enough to calculate more numbers in this sequence? B(n+1) is gotten by taking B(n) steps in the counterclockwise spiral pictured here.
    >> Anonymous 03/11/10(Thu)09:34 No.492045
         File1268318088.png-(49 KB, 727x933, latex3.png)
    49 KB
    Again,
    have you got the balls to calculate more numbers in this sequence? R(n+1) is gotten by taking R(n) steps in the counterclockwise spiral pictured here.

    A program to calculate these would be very handy but it seems it would be a fucker to code.
    >> Anonymous 03/11/10(Thu)09:37 No.492050
         File1268318231.png-(32 KB, 723x648, latex4.png)
    32 KB
    Still,
    I dare you to calculate more numbers in this sequence. The same way as before. I have yet to muster the energy to get up to 13, as it's pretty bothersome.
    >> Anonymous 03/11/10(Thu)09:45 No.492061
         File1268318756.jpg-(67 KB, 750x600, 1261341459115.jpg)
    67 KB
    Hey /sci/, are you manly enough to make a function expressing the intensity of the smell of her vagina in relation to her level of hygiene?
    >> Anonymous 03/11/10(Thu)09:56 No.492072
         File1268319378.png-(32 KB, 727x673, latex5.png)
    32 KB
    Finally,
    I bet you can't handle calculating twenty more numbers of this sequence and then calculating the sequence S(n)=B(n)A(n)R(n)L(n).

    Another interesting thing to look at would be the sequences PY(n)=m(f1(Y(n))) where Y=BRAL and f1(Y(n)) gives the coordinates for the nth number in sequence Y and, as it appeared above, m=max(nk) is the shell the coordinates (nk) are on. So, for example,
    PB(1)=0
    PB(2)=1
    PB(3)=1
    PB(4)=2 (I now notice that there's an error in my code, it's supposed to be 1221 not 1211
    PB(5)=3
    PB(6)=4
    PB(7)=6
    PB(8)=9
    PB(9)=11
    PB(10)=16
    PB(11)=23
    PB(12)=33
    PB(13)=47

    Also, if you notice any more mistakes, please tell me.
    >> look at me, I'm showing off! Anonymous 03/11/10(Thu)10:07 No.492086
    Here's the code for the B-sequence, if someone's interested. You need \usepackage[all]{xy}.

    \begin{displaymath}
    \xymatrix{
    43_{-3,3}\ar@{.}[r]\ar@/_/[d]_{18} & 44_{-2,3}\ar@{.}[r]\ar@/_/[l]_{17} & 45_{-1,3}\ar@{.}[r]\ar@/_/[l]_{16} & 46_{0,3}\ar@{.}[r]\ar@/_/[l]_{15} & 47_{1,3}\ar@{.}[r]\ar@/_/[l]_{14} & 48_{2,3}\ar@{.}[r]\ar@/_/[l]_{13} & 49_{3,3}\ar@{.}[r]\ar@/_/[l]_{12} & \ldots\\
    42_{-3,2}\ar@{.}[u]\ar@/_/[d]_{19} & 21_{-2,2}\ar@{.}[r]\ar@/_/[d]_8 & 22_{-1,2}\ar@{.}[r]\ar@/_/[l]_7 & 23_{0,2}\ar@{.}[r]\ar@/_/[l]_6 & 24_{1,2}\ar@{.}[r]\ar@/_/[l]_5 & 25_{2,2}\ar@{.}[r]\ar@/_/[l]_4 & 26_{3,2}\ar@{.}[d]\ar@/_/[u]_{11}\\
    41_{-3,1}\ar@{.}[u]\ar@/_/[d]_{20} & 20_{-2,1}\ar@{.}[u]\ar@/_/[d]_9 & 7_{-1,1}\ar@{.}[r]\ar@/_/[d]_2 & \textcolor{red}{\mathbf{8}}_{0,1}\ar@{.}[r]\ar@/_/[l]_1 & 9_{1,1}\ar@{.}[r]\ar@/_/[l]_4 & 10_{2,1}\ar@{.}[d]\ar@/_/[u]_3 & 27_{3,1}\ar@{.}[d]\ar@/_/[u]_{10}\\
    40_{-3,0}\ar@{.}[u]\ar@/_/[d]_{21} & 19_{-2,0}\ar@{.}[u]\ar@/_/[d]_{10} & 6_{-1,0}\ar@{.}[u]\ar@/_/[d]_3 & \textcolor{red}{\mathbf{1}}_{0,0}\ar@{.}[r]\ar@/_/[d]_1 & 2_{1,0}\ar@{.}[d]\ar@/_/[u]_3 & 11_{2,0}\ar@{.}[d]\ar@/_/[u]_2 & 28_{3,0}\ar@{.}[d]\ar@/_/[u]_9\\
    39_{-3,-1}\ar@{.}[u]\ar@/_/[d]_{22} & 18_{-2,-1}\ar@{.}[u]\ar@/_/[d]_{11} & 5_{-1,-1}\ar@{.}[u]\ar@/_/[d]_4 & \textcolor{red}{\mathbf{4}}_{0,-1}\ar@{.}[l]\ar@/_/[r]_1 & 3_{1,-1}\ar@{.}[l]\ar@/_/[u]_2 & \textcolor{red}{\mathbf{12}}_{2,-1}\ar@{.}[d]\ar@/_/[u]_1 & 29_{3,-1}\ar@{.}[d]\ar@/_/[u]_8\\
    38_{-3,-2}\ar@{.}[u]\ar@/_/[d]_{23} & 17_{-2,-2}\ar@{.}[u]\ar@/_/[d]_{12} & 16_{-1,-2}\ar@{.}[l]\ar@/_/[r]_5 & 15_{0,-2}\ar@{.}[l]\ar@/_/[r]_6 & 14_{1,-2}\ar@{.}[l]\ar@/_/[r]_7 & 13_{2,-2}\ar@{.}[l]\ar@/_/[u]_8 & 30_{3,-2}\ar@{.}[d]\ar@/_/[u]_7\\
    37_{-3,-3}\ar@{.}[u] & \textcolor{red}{\mathbf{36}}_{-2,-3}\ar@{.}[l]\ar@/_/[r]_1 & 35_{-1,-3}\ar@{.}[l]\ar@/_/[r]_2 & 34_{0,-3}\ar@{.}[l]\ar@/_/[r]_3 & 33_{1,-3}\ar@{.}[l]\ar@/_/[r]_4 & 32_{2,-3}\ar@{.}[l]\ar@/_/[r]_5 & 31_{3,-3}\ar@{.}[l]\ar@/_/[u]_6\\
    }
    \end{displaymath}
    >> Anonymous 03/11/10(Thu)10:08 No.492089
    >>492086
    Oh, and \usepackage{color} too.
    >> Anonymous 03/11/10(Thu)10:15 No.492103
         File1268320504.jpg-(19 KB, 400x500, imggeorge carlin1.jpg)
    19 KB
    why does Darwin look like a balder and buff George Carlin?
    >> Anonymous 03/11/10(Thu)10:17 No.492109
    >>492103

    Size of beard is directly related to intelligence.
    >> Anonymous 03/11/10(Thu)10:55 No.492207
    This problem is pointless. If you're a mathfag try to go beyond number crunching. Learn some Linear Algebra or something.
    >> Anonymous 03/11/10(Thu)11:13 No.492258
    >>492109
    Then /v/ and /a/ would be full of intelligent people.
    >> marsmar 03/11/10(Thu)18:03 No.494250
         File1268348597.jpg-(20 KB, 401x271, carlin-looks-like-darwin.jpg)
    20 KB
    >>492103
    >> Anonymous 03/11/10(Thu)18:07 No.494274
    >>494250
    the names also resonate

    "djohrdje karlinn"
    "tsharls darwinn"

    George Carlin
    Charles Darwin

    hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm



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