I don't know.

You should be able to.

13

You have to be asian

x=12

x-7=19+x
x-26=x

sorry bro, there aint no answer,

they're parallel

>x - 7 = 19 = x
>x = 26 + x
>0 = 26

http://answers.yahoo.com/question/index?qid=20080625095804AAwfJi8

>>33182003
12-7 = 19 + 12

are you on crack ?

x
||
8

http://www.wolframalpha.com/input/?i=x+-+7+%3D+19+%2B+x

Not even the internet knows

>>33181919

I'm not sure why you are even trying to answer this.

How can you answer something that has no possible answer in the first place?

mod 26

You can't solve this nincompoops

There is no answer

You can solve a problem by proving that there is no answer.

Its impossible to solve for x. That should be obvious.

"x" marks the spot.
7 is the magic number.
19 is the highest prime number under 20.

Therefore, at location "x" the proper magic sign will lead you to the "prime" treasure of the 20th century. I've already figured out your game, Riddler, and beaten you to the punch!

idk
x=13?

Assume 7 is a variable. The variable 7 has a value of -19. X is all reals.

>>33182036

yes X = 26

2x = 26
x = 13

2x = 12
x = 6

so x factors to 6 or 13

so (x-6)(x-13) = 0

>>33181919

dude in pretty cure they give the answer

>>33181977
>>33182525
retarded fags

The equation is the wrong way. Instead of

x - 7 = 19 + x,

x + 7 = 19 - x

x = 6

inb4 everyone bitches about me flipping shit around

x = 26 + x

x + 26 -7 = 19 + x

x + 19 = 19 + x

x = x

x = x + 26 dumbasses

x = -13.

Ffs, I thought anon at least covered integers.

solved it faggots

x = x + 26

x/x = (x+26)/x

(x+26)/x = 1

1 + 26/x = 1

26/x = 0

so x = infinity

>>33182844

I'm so using this the next time I have to update our job-application questionnaire.

>>33182844
Undefined

>>33182844
Infinity does not work that way.

This problem is easy for a genius like me you bakas.

>>33182972
Thought it was the other way, sorry

x=-6
if x-7=19+x
Then, if you square both sides (x-7)^2=(19+x)^2
That equals x^2+-14x+49=361+38x+x^2
Now, you take the square root of those.
±sqrt(x^2+-14x+49)=±sqrt(361+38x+x^2)
Since the square root of it can be both negative and positive
Therefore,
±(x-7)=±(19+x)
You now calculate all the solutions
+(x-7)=-(19+x)
x-7=-19-x
Then, 2x=-12
Therefore, x=-6

Prove me wrong, fuckers

>>33183026
3<i

>>33183065
Take x = 1
Square both sides
x^2 = 1
Then take the square root
Since square root can be positive or negative,
x = -1
Therefore -1 = 1

>>33183158
Prove that it's not true.

>>33182998
does now

\begin{eqnarray*}
x-7 &=& 19+ x\\
x &=& x + 26\\
x/x &=& \dfrac{x+26}{x}\\
1 &=& 1 + \dfrac{26}{x}\\
0 &=& \frac{26}{x}\\
x &=& \infty
\end{eqnarray*}

>>33183072
i<3 you retard.

>>33183065
-6 - 7 != 19 - 6
You've been proved wrong.

>Not even 2chan knows
sauce

>>33182683
Dumbass teacher status:
[X] TOLD
[ ] Not told